Applied 30 Home Time

Tuesday, October 10, 2006

Creative solutions

As I just said in class, we don't use creativity often enough to solve 'typical' unit problems. Take a few minutes with the people in your group, and discuss electronically (either as comments or separate posts), the solution to a problem like this.....use any resources that you can find.

Record, in detail, your 'thought' process in solving this problem...Have fun!


"A playoff football game draws 36 500 fans. Depending on where their seats were, the ticket prices for the game were $35 or $20. The home
team realized ticket revenue of $940 000 for the game. How many of
each type of ticket were sold?"

11 Comments:

At 1:14 PM, Blogger Capt Krunch said...

Anyone got it yet?

 
At 1:16 PM, Blogger a.l.y.s.s.a.d.a.w.n said...

This comment has been removed by a blog administrator.

 
At 1:34 PM, Blogger a.l.y.s.s.a.d.a.w.n said...

This comment has been removed by a blog administrator.

 
At 1:39 PM, Blogger caitlynd said...

Laura and Caity:

First we identified the independent variable (x) as the # of $35 ticket holders.

If there were x # of $35 ticket holders, there had to have been 36 500 - x $20 ticket holders.

So... revenue = sales(price)
and in this case;
940 000 =(35x)+[(20)(36500-x]

Here is what our solution looks like:

1.Let x= # of $35 ticket holders

2.Let 36000-x= # of $20 ticket holders

3.R=S(P)

4.940 000=(35x)+[(20)(36500-x)]

5.940 000=35x + 730 000-20x

6.940 000=15x + 730 000

7.210 000 = 15x
------------ <--(divide);)
15

8.X = 14 000

. IF X= 14 000, THERE
. . ARE 14 000 $35 TICKET HOLDERS.
AND THERE ARE 36 500 - 14 000 WHICH EQUALS 22 500 $20 TICKET HOLDERS.
THAT GIVES YOU A TOTAL REVENUE OF $940 000.

 
At 1:57 PM, Blogger marty said...

Marty and Jordan

What we did was enter all possible combinations of 35 and 20 dollar ticket holders into excel. To figure out the revenue for each we put in =(A1*20)+(B1*35),A1 being 20 dollar tickets and B1 being 35 dollar tickets. We dragged it down and got the answer:
There were 22500 $20 ticket holders and 14000 $35 ticket holders.

 
At 2:31 PM, Blogger chris_06 said...

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At 2:37 PM, Blogger chris_06 said...

to find the awnser first i put in all the ways that people could have the $20 and $35 tickets and scrolled down with excell.....

To find the revenue i just multiplied the amount of people by the price
The awnse ended up being 22500 people had $20 tickets and 14000 people had $35

 
At 11:17 PM, Blogger KaylaMarie said...

I Let a represent= $35 dollar tickets
b represent= $20 dollar tickets
L1= a+b=36500
L2= 35a+20b=940000
so..
a=36500-b
35(36500-b)+20b=940000
1277500-35b+20b=940000
1277500-15b=940000
-15b=-337500
b=22500
so then if..
a=36500-b
=36500-22500
=14000
At the playoff football game $14,000 of $35 dollar tickets were sold and $22,500 of $20 dollar tickets were sold.

 
At 12:55 PM, Anonymous michelle said...

x represents= $35 tickets
y represents= $20 tickets

x+y=36500
x=36500-y

35(36500-y)+20y=940000
1277500-35y+20y=940000
1277500-15y=-337500
-15y=-337500
y=22500

x=36500-y
x=36500-22500
x=14000

 
At 12:56 PM, Blogger Jaimi said...

Let X= the nuber of $35 ticket holders.

36500-x= $20 ticket holders

Revenue= Price(number of tickets sold)

$35 TICKET HOLDERS
940000=(35(x))+(20(36500-x))940000=.35x+730000-20x
210000=15x/15
14000=x

$20 TICKET HOLDERS
365000-14000=22500

There will be 14000 $35 ticket holders and 22500 $20 ticket holders.

 
At 1:13 PM, Blogger Capt Krunch said...

Tyler & Mark

We made a simple formula on a piece of paper.
940,000=(a*20)+(b*35)
Then using the variables, we "guessed and checked" using the calculator.

First we cut the number of tickets in half and let one half of the tickets be $20 and the others $35.

This didn't give us the answer of couse but gave us a better idea of how many of each ticket there was.

Then we did the $20 tickets 1/3 of the total number of tickets and the $35 tickets at 2/3. We plugged in our new values into the vaiables.

This time is gave us even a better idea of how many tickets there were for each.

We contiued this until we got the right variables.
# of $35 tickets=14,000
# of $20 tickets=22,500

 

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